An alloy of copper, gold, silver is found to have Cu atoms forming simple cubic lattice. If Ag atoms occupy all the face centres and Au atoms at the body centres what is the simplest formula of the alloy?

Asked by rajuharan | 26th Jan, 2017, 06:46: PM

Expert Answer:

Cu is forming simple cubic lattice
So, effective no. of Cu atoms in the unit cell = 1/8 × 8 = 1 Cu
 
Ag occupy all the face centres
So, effective no. of Ag atoms in the unit cell = 1/2 × 6 = 3 Ag
 
Au atom at the body centre
So, effective no. of Au atom in the unit cell = 1 Au
 
Thus, the simplest formula of the alloy = CuAg3Au 

Answered by Prachi Sawant | 27th Jan, 2017, 10:30: AM