Alluminium wire of resistance is pulled so that its length becomes 4 times its origional length. find the new resistanceof the wire in terms of its original resistance

Asked by Amoolya Kamuni | 22nd Apr, 2014, 08:11: PM

Expert Answer:

Let the original length of wire be L, cross sectional area be A

Then resistance,

Now length of wire L in increased 4 times by pulling i.e L'=4L .It means its cross sectional area will become A/4 i.e A'=A/4

Then new resistance will be

Answered by  | 22nd Apr, 2014, 10:17: PM

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