CBSE Class 10 Answered
algebra
Asked by poojathally | 19 Feb, 2010, 10:01: PM
Expert Answer
R - Initial number of rows, S - Initial number of seats per row.
RS - Initial total number of seats.
As we do 2R, we get S-10, and total number of seats also increase,
(2R)(S-10) = RS + 300
2RS - 20R = RS + 300
But R = S ..........Number of rows was equal to the number of seats in each row.
2R2 - 20R = R2 + 300
R2 - 20R - 300 = 0
R = [20±(400+1200)]/2 = 30 and -10.
(1) The number of rows in original arrangement were, 30.
(2) The number of seats after the rearrangment were, (30)(30) + 300 = 1200.
Regards,
Team,
TopperLearning.
Answered by | 20 Feb, 2010, 05:47: AM
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