Air contains 20% oxygen by volume how much volume of air will be required for combustion of 100 cc acetylene

Why we use at last as 100/20*250

Asked by gchoudhary2697 | 4th Aug, 2019, 09:55: AM

Expert Answer:

2C2H2 + 5O2 → 4CO2 + 2H2O

2 moles of C2H2 react with 5 moles of O2

1 mole of C2H = 22.44 cc

100 cc of C2H 

equals fraction numerator 100 over denominator 22.4 end fraction

equals 4.46 space mole

      

2 moles of C2H2 react with 5 moles of O2

4.346 mole of C2H2 will react with

equals fraction numerator 4.46 cross times 5 over denominator 2 end fraction

equals space 11.16 space mole space of space straight O subscript 2

= 11.16×22.4

= 250 cc of O2

Since air contains 20% of oxygen by volume, the amount of air needed to react with 100 cc of C2H2 

equals fraction numerator 250 cross times 100 over denominator 20 end fraction

equals 1250 space cc space of space air

Answered by Varsha | 4th Aug, 2019, 05:52: PM