Air contains 20% O2 by volume. How many c.c. of air will be required for oxidation of 100 cc of acetylene

Asked by Anil | 12th May, 2017, 02:31: PM

Expert Answer:

2C2H2 + 5O2 → 4CO2 + 2H2O

2 moles of C2H2 react with 5 moles of O2

22.44 L of C2H2 reacts with (5/2) x 22.2 L moles of O2

Hence 100 cc of C2H2 will react with (5/2)x 100 cc = 250 cc of O2

Since air contains 20% of oxygen by volume, the amount of air needed to react with 100 cc of C2H2 = 250 x (100/20) = 1250 cc of air

Answered by Vaibhav Chavan | 12th May, 2017, 04:14: PM