CBSE Class 11-science Answered
A.G.P
Asked by ravikiran | 11 Jul, 2009, 06:56: PM
Expert Answer
assuming a and b tobe less than 1 sumof infinite GP
x=1+a+a2+a3.................... and y=1+b+b2+b3.......................... is
x = 1/(1-a) ....(i)
y =1/(1-b)....(ii)
simplifying (i) we get 1-a =1/x and a = (x-1)/x
Similarly (ii) will give b = (y-1)/y
Sumof 1+ab+(ab)2+(ab)3................................... will be
= 1/ (1-ab)
again ab<1
Substituting the values of a and b we get 1/ (1-ab) = xy/(x+y-1
Answered by | 13 Jul, 2009, 04:01: PM
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