abx sq.+(b sq.-ac)x-bc =0

Dear student,

 

abx² + (b² - ac)x - bc = 0

abx² + b²x - acx - bc = 0

abx² - acx + b²x - bc = 0

ax(bx - c) + b(bx - c) = 0

(ax + b) (bx - c) = 0

x = -b/a or x = c/b

We hope that clarifies your query.

Regards,

Team

TopperLearning