ABCD is a rectangle with BAC = 32°. Determine DBC.

Asked by Topperlearning User | 16th Aug, 2017, 03:11: PM

Expert Answer:

Suppose the diagonals AC and BD intersect at O.

Then, in OAB, we have

OA = OB                  [ diagonals of rectangle are equal and they bisect each other]

     OAB = OBA

       BAC = DBA

       DBA = 32°          [BAC = 32°(given)]

Now,   ABC = 90°

       DBA +DBC = 90°

       32° + DBC = 90°

         DBC = 90° - 32° = 58° 

Answered by  | 16th Aug, 2017, 05:11: PM