CBSE Class 9 Answered
ABCD is a parallelogram. The circle through A, B and C intersects CD produced at E, prove that AE=AD
Asked by | 23 Feb, 2013, 09:43: PM
Expert Answer
Answer : Given :ABCD is a parallelogram. The circle through A, B and C intersects CD produced at E
To prove : AE=AD
=> angle AED + angle ABC = 180 ... (1) (Sum of opposite angles of cyclic quadrilaterals is 180)
=> angle ADE + angle ADC = 180 ... (2) (linear pair)
=> angle ABC = angle ADC ... ........(3) (opposite angles of parallelogram are equal)
From (1) and (2)
=> angle AED + angle ABC = angle ADE + angle ADC
=> angle AED = angle ADE (using (3))
In triangle AED,
angle AED = angle ADE
=> AD = AE (equal sides have equal angles opposite to them)
Hence Proved
Answered by | 23 Feb, 2013, 10:05: PM
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