CBSE Class 9 Answered
ABCD is a cyclic quadrilateral in which AB and CD when produced meet at E and EA=ED. Prove that AD is parallel to BC and EB=EC. Sir please tell me two ways for doing this question.
Asked by Nitin Joshi | 24 Nov, 2013, 09:50: AM
Expert Answer
1) In EAD,
EA = ED
Let ∠EAD = x
Thus, ∠EAD =∠EDA = x [angles opposite to equal sides are equal]
∠BCD +∠DAB =1800
∠BCD + x = 180 [since ∠DAB =∠DAE = x]
∠BCD = 180 - x
Similarly,
∠ABC = 180 - x
∠DAB +∠ABC = x + 180 - x
∠DAB +∠ABC =1800
Similarly, ∠BCD + ∠CDA = 1800
Since the adjacent interior angles are supplementary, therefore
2) Since ,
∠EBC =∠EAD = x [corresponding angles are equal]
Similarly ∠ECB =∠EDA = x
Now, in triangle EBC,
∠EBC =∠ECB = x
Thus, EB = EC [sides opposite to equal angles are equal]
Answered by Rashmi Khot | 24 Nov, 2013, 12:37: PM
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