AB is a diameter of a circle. BC is the tangent at B as shown in the given figure. Show that PBC = BAP.

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

ABC=90o Since AB being diameter is perpendicular to tangent BC at the point of contact.

So ABP +PBC =90o (i)

Also APB =90o (angle in the semi-circle)

So BAP+ABP = 90o (ii) (using angle sum property of triangles)

From (i) and (ii),


Answered by  | 4th Jun, 2014, 03:23: PM