CBSE Class 9 Answered
A wooden block of mass 8 kg is tied to a string attached to the bottom of the tank. In equilibrium , the block is completely immersed in water. If relative density of wood is 0.8 and g = 10 m / s2 then what is the value of tension in the string.
Asked by Paresh | 18 Nov, 2015, 06:26: PM
Expert Answer
Given:
Mass of the wooden block, m= 8kg
Relative density of wood = 0.8
We know that:
The upthrust experienced by the wooden block upward will be balanced by the weight of the wooden block acting downwards + the tension on the string
i.e. Upthrust = Weight + Tension
Therefore the tension on the string = Upthrust - Weight
The upthrust experienced by the wooden block = Volume of water displaced by the block × Density of water × g
Tension on the string = Upthrust - Weight
= 100 N - (8 ×10) N
= 20 N
Therefore Tension on the sring = 20N
Answered by Yashvanti Jain | 18 Nov, 2015, 06:35: PM
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