A wire's length is increased by 25%. What % will the resistance be increased.
Asked by | 19th Mar, 2010, 10:35: AM
Expert Answer:
R 
1/L
Rf/Ri = Li/Lf where i and f refers to initial and final values respectively.
(Lf - Li)/Li = 0.25
Hence Li/Lf = 1/1.25.
Therefore,
Rf/Ri = 1/1.25
Rf = 0.8Ri
(Rf - Ri)/Ri = -0.20.
Hence resistance will decrease by 20%.
Regards,
Team,
TopperLearning.
Answered by | 19th Mar, 2010, 06:59: PM
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