A wire of resistance R and length l is bent into a square.Find the effective resistance betwe

Asked by  | 23rd Aug, 2009, 03:33: PM

Expert Answer:

Let a, be the side of the resultant square.

Between any two opposite ends, the length is 2a.

Total length = 4a = l.

Since R  l, the two resistance between opposite ends, i.e. R1 and R2 are equal and,

R1  R2  l/2  R/2. 

The equilalent resistance = R1R2/(R1+R2)

= R2/4/(R/2+R/2) = R/4   Answer.





Answered by  | 23rd Aug, 2009, 05:53: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.