a wire of resistance 50 ohm is bent in the form of closed circle.
Asked by devanshmudgal | 28th May, 2010, 07:27: PM
The diameter divides the circle into two semi circles.So, if the wire has a resistance 50 ohm, the resistances of those two equal semi circles will be 25 ohm each. These two semi circels will behave as a parallle combination.
Hence the effective resitance will be
1/R = 1/R1 + 1/R2 = 1/25 + 1/25 Hence R = 12.5 ohm
Answered by | 29th May, 2010, 11:29: AM
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