a wire of resistance 20 ohm is drawn out so that its length is increased twice its original length.determine its new resistance?

Asked by Bholanath Beura | 21st May, 2012, 06:31: PM

Expert Answer:

Length got doubled 
 
pi (r12) l1 = pi (r22) l2
 
(r12) /  (r22) = 2
 
(r22) = (r12) /2
 
So resiatnace will be 4 times & it will be 20 * 4 = 80 ohms

Answered by  | 22nd May, 2012, 10:30: AM

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