A vessel contains equal moles of helium and methane.Due to a hole in the vessel half of gaseous mixture is effused out.What is ratio of no of moles left in mixture?

Asked by Navya Benny | 3rd May, 2013, 04:02: PM

Expert Answer:

r He   = ? M CH 4   =    ?16 /4       = 2.
r CH4         M He
He  2 times faster than methane.
left over is twice as much of methane wrt He ,

Answered by  | 10th Jun, 2013, 05:42: PM

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