A vessel contains equal moles of helium and methane.Due to a hole in the vessel half of gaseous mixture is effused out.What is ratio of no of moles left in mixture?
Asked by Navya Benny | 3rd May, 2013, 04:02: PM
Expert Answer:
r He = ? M CH 4 = ?16 /4 = 2.
r CH4 M He
He 2 times faster than methane.
left over is twice as much of methane wrt He ,
Answered by | 10th Jun, 2013, 05:42: PM
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