A vector n of magnitude 8 units is inclined to x-axis at 45° , y-axis at 60° and at an acute angle with     z-axis. If a plane passes through a point (2,-1,1) and is normal to n, find the equation in vector form.

Asked by sunil2791 | 8th Dec, 2017, 07:00: PM

Expert Answer:

begin mathsize 16px style According space to space the space question comma
straight alpha equals 45 degree comma space straight beta equals 60 space then space
cos squared straight alpha plus cos squared straight beta plus cos squared straight gamma equals 1
1 half plus 1 fourth plus cos squared straight gamma equals 1
cos squared straight gamma equals 1 fourth
cosγ equals 1 half
Equation space of space straight a space normal space vector space is space
straight n with hat on top equals cosα straight i with hat on top plus cosβ straight j with hat on top plus cosγ straight k with hat on top
equals fraction numerator 1 over denominator square root of 2 end fraction straight i with hat on top plus 1 half straight j with hat on top plus 1 half straight k with hat on top
Now space find space the space equation space of space straight a space plane space in space vector space form. end style

Answered by Sneha shidid | 11th Dec, 2017, 09:17: AM