A variable force acts on a box. Find the work done on the block as it is moved from x=0m to x=20m.

Asked by Topperlearning User | 4th Jul, 2014, 04:42: PM

Expert Answer:

Work done is given by integration. Graphically it means work is the area under F vs. x graph.

W = Area under the graph
    = area of rectangle ABCD + area of trapezium CEID
    = (100 x 10) + [½ (100 + 50) x 10] = 1000 + 750 = 1750 J

Answered by  | 4th Jul, 2014, 06:42: PM