CBSE Class 11-science Answered
A variable force acts on a box. Find the work done on the block as it is moved from x=0m to x=20m.
Asked by Topperlearning User | 04 Jul, 2014, 04:42: PM
Expert Answer
Work done is given by integration. Graphically it means work is the area under F vs. x graph.
W = Area under the graph
= area of rectangle ABCD + area of trapezium CEID
= (100 x 10) + [½ (100 + 50) x 10] = 1000 + 750 = 1750 J
Answered by | 04 Jul, 2014, 06:42: PM
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