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CBSE Class 11-science Answered

<div> <p class="MsoNormal"><span style="font-size: 18.0pt; line-height: 115%;">A uniform steel rod of 1 m in length is bent in a 90 degree angle at its mid point. Determine the position of centre of mass from the corners at bent.</span></p> </div>
Asked by sudhanshubhushanroy | 25 Oct, 2017, 08:56: PM
Expert Answer
X and Y-co-ordinate of Centre of mass are given as
 
begin mathsize 12px style straight X equals fraction numerator straight m subscript 1 straight x subscript 1 plus straight m subscript 2 straight x subscript 2 over denominator straight m subscript 1 plus straight m subscript 2 end fraction end style
begin mathsize 12px style straight y equals fraction numerator straight m subscript 1 straight y subscript 1 plus straight m subscript 2 straight y subscript 2 over denominator straight m subscript 1 plus straight m subscript 2 end fraction end style
 
 
Assuming them on x and y-axis
 
 
Error converting from MathML to accessible text.
 
Error converting from MathML to accessible text.
 
Position vector from the corner =
equals straight L over 8 left parenthesis straight i plus straight j right parenthesis

Position space v e c t o r space m a g n i t u d e space from space corner space
equals space square root of open parentheses straight L over 8 close parentheses squared plus open parentheses straight L over 8 close parentheses squared end root
equals straight L over 8 square root of 2
 
 
Answered by Gajendra | 05 Dec, 2017, 07:13: PM
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