a truck weighing 1000kgf changes its speed from 36km/h to 72 km/h in 2 minutes. calculate(a) the work done by the engine& (b)its power (g=10 m/s-2)

Asked by pri | 13th Mar, 2012, 06:43: PM

Expert Answer:

w=1000 kgf (it is the force exerted by 1000kg mass)
Therefore, m=1000 kg

u=36 km/h=10 m/s

v=72km/h=20m/s

t=2 min=120 s

We know, Work done, W=F.s

F=ma=

Answered by  | 14th Mar, 2012, 11:39: AM

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