a truck of mass 5000kg traveling at 40m/s is brought to rest by applying its brakes. the truck comes to rest after traveling 20m after application of brakes. what is the kinetic energy of the truck?

Asked by  | 28th Dec, 2011, 12:00: AM

Expert Answer:

Here v=0 m/s and u= 40m/s

S= 20 m

V2-u2= 2as

-(20)2 =2x20a

-400/40=a

-10m/s2= a

K.E= ½ m v2

=1/2x 5000x40 x40                 =                      5000x20x40               = 4x 106J

Answered by  | 29th Dec, 2011, 12:49: PM

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