a train starts from a station and moves with a constant acceleration acceleration for 2 minutes. If it covers a distance of 400m in this period- find the velocity

Asked by Ayushi Joshi | 31st May, 2013, 06:10: PM

Expert Answer:

u = 0 m/s
t = 2 min = 120 sec
s = 400 m
Using second law of motion
s = ut+1/2at^2
400 = 1/2*a* 120*120
a = 0.055 m/s^2
 
Using first law of motion
v = u+at
v = 0.055*120 = 6.67 m/s

Answered by  | 31st May, 2013, 08:26: PM

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