A TRAIN STARTING FROM REST MOVES WITH A UNIFORM ACCELERATION OF 0.2M/S/S FOR 5 MINUTES . CALCULATE THE SPEED ACQUIRED AND THE DISTANCE TRAVELLED IN THIS TIME

Asked by  | 23rd Jul, 2012, 10:38: PM

Expert Answer:

acceleration,a = 0.2m/s2
time, t = 5 min = 300 s
initial velocity be u = 0m/s
 
using first equation of motion, final velocity:
v = u + at = 60 m/s
 
and according to second equation of motion, distance travelled,
s = ut + 1/2at2 = 9 km

Answered by  | 23rd Jul, 2012, 11:02: PM

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