a train passes through a tunnel which iss 750m long. T he guard finds that he remains in the tunnel for 67.55 seconds.Calculate the speed of the train in km/hr?

Asked by Nivedita | 15th Oct, 2015, 09:19: PM

Expert Answer:

L e n g t h space o f space t h e space t u n n e l equals 750 space m equals 750 over 1000 space k m T i m e space t a k e n space t o space c r o s s space t h e space t u n n e l equals 67.55 space s e c o n d s equals fraction numerator 67.55 over denominator 3600 end fraction space h o u r T h u s space s p e e d space o f space t h e space t r a i n equals fraction numerator D i s tan c e over denominator T i m e end fraction equals fraction numerator 750 over 1000 over denominator fraction numerator 67.55 over denominator 3600 end fraction end fraction equals 750 over 1000 cross times fraction numerator 3600 over denominator 67.55 end fraction equals 39.97 space k m divided by h o u r space open parentheses a p p r o x. close parentheses

Answered by Vimala Ramamurthy | 16th Oct, 2015, 12:14: PM

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