a thin circular wire of radius R rotates about its vertical diameter with an angular frequency w (Omega). Show that a small bead on the wire remains at its lowermost point for under-root g/R = or greater than omega. What is the angle made by the radius vector joining the centre to the bead with vertical downward direction for omega = underroot 2g/R?

Asked by ayushikas | 14th Jan, 2012, 06:20: PM

Expert Answer:

Answered by  | 23rd Jan, 2012, 06:09: PM

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