A test charge q is moved without acceleration from A(6,0) to C (2,0) along the path from A to B to C IN ELECTRIC FIELD E
CALCULATE THE PD ACROSS A TO C
AT WHICH POINT (OF THESE TWO) THE ELECTRIC POTENTIAL IS MORE AND WHY??
Asked by vasturushi | 28th Dec, 2017, 12:38: PM
Expert Answer:
Electric field is a conservative force
therefore, the Potential difference between A and C would be same as Potential between A and B
Potential difference A and B
= E x l(AB)
= E x 4
= 4E Volt
Potential difference reduces the direction of Electric field
therefore A will be at more potential
Potential difference A and B
= E x l(AB)
= E x 4
= 4E Volt
Potential difference reduces the direction of Electric field
therefore A will be at more potential
Answered by Gajendra | 28th Dec, 2017, 02:26: PM
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