A test charge q is moved without acceleration from A(6,0) to C (2,0) along the path from A to B to C IN ELECTRIC FIELD E 
CALCULATE THE PD ACROSS A TO C
AT WHICH POINT (OF THESE TWO) THE ELECTRIC POTENTIAL IS MORE AND WHY??

Asked by vasturushi | 28th Dec, 2017, 12:38: PM

Expert Answer:

Electric field is a conservative force
therefore, the Potential difference between A and C would be same as Potential between A and B
Potential difference A and B
 
= E x l(AB)
= E x 4
= 4E Volt


Potential difference reduces the direction of Electric  field
 
therefore A will be at more potential 
 

 

Answered by Gajendra | 28th Dec, 2017, 02:26: PM