A tank 5m high is half filled with water and then is filled to the top with oil of density of 0.85 g/cc. What is the pressure at the bottom of the tank due to these liquids in dyne per sq. cm.

Asked by Srishti Majumdar | 22nd Oct, 2010, 06:50: PM

Expert Answer:

Dear student
 
The pressure at the bottom of the tank will be due to the [weight of water through a height of 250 cm + weight of oil through a height of 250 cm ] divided by unit area at the bottom, i.e., 1 cm2.
 
Weight of water through a height of 250 cm =mass x g = Vol x ρw x g = 250 x 1 x ρw x g = 250 g  (recall that ρw = 1 g/cc)
 
 
Weight of oil through a height of 250 cm = mass x g = Vol x ρoil x g = 250 x 1 x ρoil x g =212.5 g
 
Total weight of liquids at the bottom = 250 g + 212.5 g = 462.5 g
 
Pressure at the bottom of the tank = P = 462.5 g /1 cm2 = 453250 dyn/cm2     
 
We hope  that clarifies your query.
 
Regards
Team
TopperLearning
 

Answered by  | 23rd Oct, 2010, 10:20: AM

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