A takes 10 days less then the time taken by B to finish a piece of work. If both A and B (cont)

Asked by Ayush Saraf | 4th May, 2010, 11:05: AM

Expert Answer:

Dear Student,

The solution to your problem is as follows:

Let the time taken by B be t days to finish a piece of work. Then A takes (t-10) days.

 

Therefore,

Amount of Work done in 1 day by B = 1/t

Amount of work done in 1 day by A = 1(t-10)

Amount of work done in 1 day by A and B together

Therefore, A and B can complete the task together in

But it is given that A and B together complete the task in 12 days.

But t=4 can't be the answer because in that case time taken by A will be -6 days, and time can't be negative.

Therefore, t=30.

 

B takes 30 days to complete the work alone

A takes 20 days to complete the work alone.

 

Regards Topperlearning.

Answered by  | 4th May, 2010, 02:37: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.