A sulphuric acid solution contains 98 % (m/v) H2SO4. The density of the solution is 1.98 g cm-3.. The molarity and molality respectively of the solution are ------

Asked by Paresh | 14th Jan, 2016, 08:28: AM

Expert Answer:

begin mathsize 11px style Given colon Density space equals space 1.98 space straight g divided by cm cubed Weight space of space straight H subscript 2 SO subscript 4 space equals space 98 space straight g Weight space of space Solution space equals space 100 space straight g  therefore space Volume space of space Solution space equals space fraction numerator 100 over denominator 1.98 end fraction space equals space 50.5 space cm cubed  Weight space of space Solvent space left parenthesis Water right parenthesis space equals space 100 space minus space 98 space equals space 2 space straight g Molecular space weight space of space straight H subscript 2 SO subscript 4 space equals space 98 space straight g divided by space mol  therefore space Number space of space moles space in space 98 space straight g space equals space fraction numerator Given space Mass over denominator Molar space Mass end fraction space equals space straight m over straight M space equals space 98 over 98 space equals space 1 space mol  Molality space equals space fraction numerator No. space of space Moles space of space straight a space solute over denominator Weight space of space Solvent end fraction space cross times space 1000 space space space space space space space space space space space space space space space space equals space 1 half space cross times space 1000 space equals space bold 500 bold space bold mol bold divided by bold kg Molarity space equals space fraction numerator No. space of space Moles space of space straight a space solute over denominator Weight space of space Solution end fraction space cross times space 1000 space space space space space space space space space space space space space space space space space equals space fraction numerator 1 over denominator 50.5 end fraction space cross times space 1000 space equals bold 19 bold. bold 8 bold space bold mole bold divided by bold L bold space bold H subscript bold 2 bold SO subscript bold 4 bold space end subscript end style

Answered by Hanisha Vyas | 15th Jan, 2016, 03:17: PM