CBSE Class 10 Answered
A straight highway leads to foot of a tower. A man
standing at the top of the tower observes a car at an angle of depression of
30o, which is approaching the foot of the tower with a uniform
speed. Six seconds later the angle of depression of the car is found to be 60o.
Find the time taken by the car to reach the foot of the tower from this
point.
Asked by Topperlearning User | 27 Jul, 2017, 11:02: AM
Expert Answer
Let PQ = h metres be the height of the tower. P is the top of the tower.
The first and second positions of the car are at A and B respectively.
APX = 30o PAQ = 30o
BPX = 60o PBQ = 60o
Let the speed of the car be x m/second
Then, distance AB = 6x meters
Let the time taken from B to Q be n seconds
BQ = nx metres
In PAQ,
...(1)
In PBQ,
...(2)
From (1) and (2),
n = 3
Hence, the time taken by the car to reach the foot of the tower from B is 3 seconds.
Answered by | 27 Jul, 2017, 01:02: PM
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