A stone is dropped from the edge of a roof.
Asked by samrid vinod samridvinod | 10th Sep, 2013, 06:41: PM
initial velocity, u = 0
distance dropped be h
if h = 4.9 m
we know acceleration, g = 9.8 m/s.s
thus using second equation of motion, h = ut + 1/2gt2
we can find time required t.
for that t, we can use first equation of motion to find final velocity, v
v = u + gt
for last part, the acceleartion remains same, only velocity varies.
Answered by | 11th Sep, 2013, 12:09: AM
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