A stone is allowed to fall down from the top of a tower 100m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 ms-1. Calculate when and where the two stones will meet?(take g = 10ms-2) how to do it ???i didnt understand.....

Asked by Saloni Bansal | 16th Jul, 2013, 06:30: PM

Expert Answer:

Height of the tower = 100m

g = 10 m/s 2

velocity of projection of ground projectile = 25 m/s

Velocity of projection of the tower projectile = 0

Let the particles meet at time t and at height h

Thus,

Answered by  | 19th Jul, 2013, 09:43: AM

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