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(a)State Law of Conservation of Energy and express it in the form of an equation for a body
of mass m falling from a point A at height h, above the ground at
(i) A (ii) B at a height from ground, (iii) C.

Asked by sahasra4050 | 20 Jan, 2022, 08:53: AM

Law of conservation of energy - Energy can neither be created nor be destroyed; it can only be transformed from one form to another.Consider a body of mass m placed at A.h = AB is the height of the body above the groundu = 0 is initial velocity at Av1 = velocity of body at Cv = velocity of body at B, i.e., just above the ground(i) At point APEA = mghKEA = 0Total mechanical energy at A, EA = PEA + KEA = mgh + 0 = mgh(ii) At point Cv12-0 = 2gsv12 = 2gsKEC = PEC = mg(h-s)Total mechanical energy at C, EC = PEC + KEC = mg(h-s) + mgs = mgh(iii) At point Bv2-02 = 2ghv2 = 2ghKEB = PEB = 0Total mechanical energy at B, EB = PEB + KEB = 0 + mgh = mghThe total mechanical energy of the body at A, B and C (also at any other point in the path AB) is the same. So, the total mechanical energy of the body throughout the free fall is conserved.

Answered by Shiwani Sawant | 20 Jan, 2022, 09:18: AM

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