A standard tuning fork A has a frequency 480Hz. Another tuning fork B gives 6 beats with it. B is slightly filed and now the beat frequency is found to be 2.Find the original frequency of B.

Asked by  | 24th Feb, 2013, 12:36: PM

Expert Answer:

nB-480=6
nB>nA as B is slightly filed and now the beat frequency is found to be less.
so nB=486Hz

Answered by  | 26th Feb, 2013, 05:56: PM

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