CBSE Class 11-science Answered
A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 30 N, when the lift is stationary. What will be the reading of the spring balance, if the lift moves downward with an acceleration of 5 ms-2.
Asked by Topperlearning User | 05 Jun, 2014, 09:24: AM
Expert Answer
When the lift is stationary:
The reaction is equal to the weight of the man, that is
R = Mg = 30 N
Therefore, M = 30/g = 30/9.8 = 3.06
When the lift is moving:
Let R1be the reaction, when the lift is moving with an acceleration a = 5 ms-2 in the downward direction.
Then, we have
R1= M (g-a) = 3.06 × (9.8 - 5) = 14.7 ≈ 15 N
Answered by | 05 Jun, 2014, 11:24: AM
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