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<div>A spherical conducting sphere of inner radius R1 and outer radius R2 has a charge Q.A charge q is placed at the centre of the shell.What is the surface charged density on the(1)inner surface</div> <div>(2)outer surface of the shell?</div> <div>&nbsp;</div> <div>What is the expression for the electric field at a point to x&gt;R2 from the centre of the shell?</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div> <div>&nbsp;</div>
Asked by Rajeev | 12 May, 2015, 03:28: PM
The total charge enclosed for the inner sphere is 'q'.

Hence, the surface charge density for the inner sphere is

The total charge enclosed for the outer sphere is 'Q+q'.

Hence, the surface charge density for the outer sphere is

The electric field at a point at a distance x from the sphere is given by Gauss' law

by imagining a sphere of radius x.

Answered by Romal Bhansali | 12 May, 2015, 04:14: PM

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