A solution containing 10.2g of glycerin per litre is found to be isotonic with 2% solution of glucose (molar mass = 180 g mol-1). Calculate the molar mass of glycerin.

Asked by Topperlearning User | 20th Jun, 2016, 03:42: PM

Expert Answer:

For solution of Glucose             pA V= n RT ----- (1)
                                                                  pA x 0.1L = ( 2/180 )x R x T
                                                                
 
For solution of Glycerin          pB V= n RT ----- (2)
                                     pB x 1L = ( 10.2/MB )x R x T
                                                   pA  = pB
                        ( 2/180 )x R x T/ 0.1 = ( 10.2/MB )x R x T/ 1

                                                MB = 91.8 gmol-1

Answered by  | 20th Jun, 2016, 05:42: PM