a solid AB has nacl structure .if the radius of cation is 100pm,what is the radius of anion B.

Asked by amanj | 10th Apr, 2014, 04:08: PM

Expert Answer:

Solution :
Radius of Na+ = 100pm
 
Radius of Cl-  = ?
 
Radius ratio(r+/r-) = 0.414
 
Radius ratio(r+/r-)  = r(Na+)    =     100     = 241pm
                                  r(Cl-)             0.414

Answered by  | 10th Apr, 2014, 05:02: PM

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