a small amount of cuO is dipped in the dilute solution of HCl. give the changes that would take plac

Asked by  | 24th Jun, 2008, 07:10: PM

Expert Answer:

 

 

The following reaction takes place: 

CuO(s) + 2HCl(aq) → CuCl2(aq) + H2O(l)

Answered by  | 4th Jul, 2008, 12:09: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.