a semicircular sheet of metal of dia 28cm is bent into an open coincal cup. find the depth & volume
Asked by vaibhavkalind | 16th Nov, 2009, 09:27: PM
Expert Answer:
The slant height of the so formed cone will be the radius of the semicircle and the perimeter of the base circle is the diameter of the original semicircle.
Hence s = 14 cm and 2πr = 28 cm, r = 14/π
The depth = (s2-r2)1/2 = 13.27 cm
Volume = πr2h/3 = π(14/π)2(13.27)/3 = 276.11 cm3
Regards,
Team,
TopperLearning.
Answered by | 16th Nov, 2009, 09:58: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change