a semicircular sheet of metal of dia 28cm is bent into an open coincal cup. find the depth & volume

Asked by vaibhavkalind | 16th Nov, 2009, 09:27: PM

Expert Answer:

The slant height of the so formed cone will be the radius of the semicircle and the perimeter of the base circle is the diameter of the original semicircle.

Hence s = 14 cm and 2πr = 28 cm, r = 14/π

The depth = (s2-r2)1/2 = 13.27 cm

Volume = πr2h/3 = π(14/π)2(13.27)/3 =  276.11 cm3




Answered by  | 16th Nov, 2009, 09:58: PM

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