A rocket is fired with a velocity 0.6 times the escape velocity on the surface of earth.How high will it go from the surface?
Asked by MANISHA MOHANTY | 25th Nov, 2013, 11:28: AM
The velocity of rocket = v = 0.6 × 11.2 = 6.72 km/s = 6720 m/s
Radius of earth is = RE = 6.4 × 106 m
Mass of earth is = ME = 6 × 1024 kg
The velocity with which the rocket is fired becomes the critical velocity of it.
Thus, the rocket can go up to a height h above the earth's surface.
Hence, we have
Answered by Romal Bhansali | 26th Nov, 2013, 09:43: AM
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