A resistance R is connected across a cell of emf E and internal resistance r. A potentiometer now measures the pot. diff. btw the terminals of the cell as V. pls explain how.

Asked by Ann Liza Tharakan | 12th Jul, 2013, 07:44: AM

Expert Answer:

The expression is given as

r = [(E - V) / V].R

this comes out because

the total current flowing in a wire is given as

I = IE - IV


V/R = E/r - V/r

which can be rearranged to give the above relation


Answered by  | 12th Jul, 2013, 10:54: AM

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