A ray of light passing throa prism of angle 50 deg & RI 1.55 is incident at 35 deg. Calculate r1, r2, deviation & angle of emergence?

Asked by PAYASWINI YP | 26th Jun, 2013, 08:22: PM

Expert Answer:

A = 50 degree
n  = 1.55, n0 = 1
i = 35 degree
 
Now at the first surface
n/n0 = sin i / sinr1
sinr1 = sin35/1.55 = 0.337 
r1 = 21.89 degree
 
Now, A = r1+r2
50 = 21.89 +r2
r2 = 28.11 degree
 
Now, at the second surface, also
n/n0 = sin r2 / sini2 (i2 is the angle of emergence)
sini2 = sin(28.11)/1.55 = 0.275
i2 = 17.78 degree
 
Furthermore, n = sin((A+D)/2)/sinA/2
sin((A+D)/2) = 1.55*sin25
sin((A+D)/2) = 0.593
(A+D)/2 = 40.42
A+D = 80.84
D = 80.84-50
D = 30.84 degree

Answered by  | 27th Jun, 2013, 07:19: AM

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