A ray of light enters a diamond from air . If the refractive index of diamond is 2.42 , by what percent does the speed of light reduce on entering the diamond

 

Asked by Poorvi | 3rd Jan, 2018, 09:45: AM

Expert Answer:

Refractive index μ = c/v . where c and v are speed of light in air and refracting medium respectively.
 
hence v = c/μ = c/2.42 = 0.413×c
 
hence speed of light in diamond is reduced to 41.3% of original value in air

Answered by  | 3rd Jan, 2018, 05:46: PM

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