Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

A question on spring extension
Asked by Pallavi Chaturvedi | 18 Oct, 2013, 01:10: PM
Expert Answer
When body is lowered to mean position, its extension is x.
According to Hooke's law:
 
F = kx = mg
Thus, we have
 
x = mg/k                        ...... (1)
 
Now, when the spring is allowed to fall under gravity, it oscillates about its mean position.
 
Let y be the amplitude of vibration of spring.
 
Then, by conservation of energy at the lowest point
 
½ky2 = mgy
 
Thus, we have
 
y = 2mg/k                        ...... (2)
 
Hence, from (1) and (2), we can say that
 
y = 2x
 
Hence, correct option is b.
Answered by Romal Bhansali | 18 Oct, 2013, 07:29: PM
CBSE 11-science - Physics
Asked by vaniimtiyaz630 | 12 May, 2022, 12:19: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by bandarirohinipriya | 08 Feb, 2022, 09:46: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by unnatibhise08 | 22 Dec, 2021, 08:46: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by ayushmishradbb | 11 Jun, 2020, 09:07: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by shrawanimamidwar | 22 May, 2020, 01:20: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by mahanteshsurpur5 | 07 May, 2020, 08:13: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Harshhacker2580 | 04 May, 2020, 05:32: PM
ANSWERED BY EXPERT
Season Break Offer!
Get 60% Flat off instantly.
Avail Now
×