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# CBSE Class 11-science Answered

A question on spring extension
Asked by Pallavi Chaturvedi | 18 Oct, 2013, 01:10: PM
When body is lowered to mean position, its extension is x.
According to Hooke's law:

F = kx = mg
Thus, we have

x = mg/k                        ...... (1)

Now, when the spring is allowed to fall under gravity, it oscillates about its mean position.

Let y be the amplitude of vibration of spring.

Then, by conservation of energy at the lowest point

½ky2 = mgy

Thus, we have

y = 2mg/k                        ...... (2)

Hence, from (1) and (2), we can say that

y = 2x

Hence, correct option is b.
Answered by Romal Bhansali | 18 Oct, 2013, 07:29: PM

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