A proton is moving with a velocity of 5 × 10^5 m/s along the Y-direction. It is acted upon by an electric field of intensity 10^5 V/m along the X-direction and a magnetic field of 1 Wb/m^2 along the Z-direction. What is the Lorentz Force on the particle?

Asked by rishabhsankla1 | 19th Sep, 2019, 07:59: PM

Expert Answer:

Lorent'z force is given by
F with rightwards arrow on top equals q E with rightwards arrow on top plus q V with rightwards arrow on top cross times B with rightwards arrow on top
F with rightwards arrow on top equals 1.6 cross times 10 to the power of negative 19 end exponent C cross times 10 to the power of 5 V divided by m i with hat on top plus 1.6 cross times 10 to the power of negative 19 end exponent C cross times 5 cross times 10 to the power of 5 cross times 1 W b divided by m squared i with hat on top
F with rightwards arrow on top equals 9.6 cross times 10 to the power of negative 14 end exponent i with hat on top N

Answered by Utkarsh Lokhande | 19th Sep, 2019, 08:32: PM

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