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CBSE Class 11-science Answered

A projectile is fired at any angle theta. find all possible
Asked by sangamsaini2009 | 24 Aug, 2024, 08:35: AM
answered-by-expert Expert Answer

Let u be the initial projection velocity at initial angle of projection θ .

Maximum height H reached by projectile from the level of projection is

H = ( u2 sin2θ ) / ( 2 g )

Range R , Maximum horizontal distance is

R = ( u2 sin 2θ ) / ( g )

Answered by Thiyagarajan K | 24 Aug, 2024, 10:04: AM

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