CBSE Class 10 Answered

The conductor AB is connected in parallel to both the resistors (4 Ω and 6 Ω).

Hence it is short circuiting both the resistors. Therefore potential difference between both the resistors is same and it is equal to zero.

 Now 2 Ω is the only resistance connected in the circuit with 20 V cell.

Therefore current flowing through the circuit (and through the wire AB) is 20/2= 10 A.

The power supplied by the battery is equal to heat dissipated by the resistor 2 Ω which is equal to (I²×R) = 10²*2= 200 watt.

Therefore option a is correct.