(A)power supplied by the battery is 200 watt
(B)current flowing in the circuit is 5A
(C)potential difference across 4ohm resistance is equal to the potential difference across 6 ohm resistance 
(D)current in wire AB is zero

Asked by Yash Sahu | 7th Apr, 2014, 10:40: AM

Expert Answer:

The conductor AB is connected in parallel to both the resistors (4 Ω and 6 Ω).


Hence it is short circuiting both the resistors. Therefore potential difference between both the resistors is same and it is equal to zero.

 Now 2 Ω is the only resistance connected in the circuit with 20 V cell.

Therefore current flowing through the circuit (and through the wire AB) is 20/2= 10 A.


The power supplied by the battery is equal to heat dissipated by the resistor 2 Ω which is equal to (I2×R) = 102*2= 200 watt.

Therefore option a is correct.

Answered by Ravindra Kapal | 7th May, 2014, 04:50: PM

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