A positive integer n when divided by 9 gives 7 as remainder.What will be the remainder when (3n-1) is divided by 9? 

Asked by araima2001 | 15th Sep, 2015, 06:54: PM

Expert Answer:

A positive integer n when divided by 9 gives remainder 7.
By using Euclids Division lemma,
n = 9q + 7    where q > 0
 
3n -1  = 3(9q + 7) - 1
3n - 1 = 27 q + 21 - 1
3n - 1 = 27q + 20
3n - 1 = 27q + 18 + 2
3n - 1 = 9(3q + 2) + 2
3n - 1 = 9Q + 2 ......(Where Q = (3q + 2))
 
Remainder is 2.

Answered by Vijaykumar Wani | 16th Sep, 2015, 10:18: AM

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